Question

ABCD is a trapezium in which AB is parallel to CD. If angle A = angle B=45 degree. Find the measures of angle C and angle D.

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Answer 1

Answer:

Step-by-step explanation:

A=∠B=45°

lets draw two lines ⏊ on line AB. Lets name there point of intersection as P and Q from left to right.

∠P = 90°

∴ ∠APD+∠PDA+∠DAP = 180° (Angel sum property)

= 90° + ∠PDA +45° = 180

= ∠PDA = 45°

∵ ∠PDC +∠PDA = ∠ADC

= 45°+90° =∠ADC

=135° = ∠ADC

∠C = ∠D (∵ There are correspondive by virtue)

∴ ∠C and ∠D equal to 135°.

Answer 2

Answer:

A=∠B=45°

lets draw two lines ⏊ on line AB. Lets name there point of intersection as P and Q from left to right.

∠P = 90°

∴ ∠APD+∠PDA+∠DAP = 180° (Angel sum property)

= 90° + ∠PDA +45° = 180

= ∠PDA = 45°

∵ ∠PDC +∠PDA = ∠ADC

= 45°+90° =∠ADC

=135° = ∠ADC

∠C = ∠D (∵ There are correspondive by virtue)

∴ ∠C and ∠D equal to 135°.