ABCD is a trapezium in which AB is parallel to CD. The diagonals AC and BD intersects at O. If OA = 6 CM and OC = 8cm
Then find the ratio of area of triangle AOD and area of triangle COD.
This question is from triangle similarity question of class 10
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given-OA=6cm OC=8cm now in trnglAOD and trnglCOD, angle AOD =angle AOC(since diagonals bisect each other) OD is common AO=OC(since diagonals bisect each other) ⇒ trnglAOD ≡ trnglCOD, (SAS postulate) we know that area of similar triangles is the ratio of the squares on their corresponding sides ⇒(area of trnglAOD÷ area of trngl COD),=OA²÷OC² =6³÷8² =36÷64 =9:16
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