ABCD is a trapezium in which AB is parallel to DC and 2AB= 3DC find the ratio of area of triangle AOB and triangle COD
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Answered by
90
Thank you for asking this question. Here is your answer:
Angle DOC = BOA (vertically opposite angles are equal)
Angle CDO = ABO (alternate interior angle)
Angle DCO = BAO
So, triangle AOB and Cod are similar
We will use the similarity rule here,
(area of triangle AOB)/(area of triangle COD) =(AB/CD)^2
=(2CD/CD)^2=4
=4:1
If there is any confusion please leave a comment below.
tanukahlon2:
We have 2AB = 3DC, But you prove with AB = 2CD
Answered by
65
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