Question

ABCD is a trapezium in which AB is parallel to DC and AD = BC. If CE is drawn parallel to AD meeting AB at E, prove the following: (a) AECD is a parallelogram (b) AD=EC (c) triangle CEB is an isosceles triangle​ (d) angle CEB = angle CBE

Answer 1

Answer:

I think so

Step-by-step explanation:

(a) AECD is a //gm

(b) no AD is not equal to EC

(c) triangle CEB is isosceles as angles E and B are 50 degrees each

(d) YES they both are equal 50 degrees