ABCD is a trapezium in which AB is parallel to DC ,BD is a digonal and E is the midpoint of AD .A line is drawn through E Parallel to AB intersecting BC at F S T ‘f’ is the midpoint of BC
Answers
Answered by
2
Answer:
hope you like have a nice day
Step-by-step explanation:
Given ABCD is a trapezium.
We have to prove, F is the mid point of BC, i.e., BF=CF
Let EF intersect DB at G.
In ΔABD E is the mid point of AD and EG∣∣AB.
∴ G will be the mid-point of DB.
Now EF∣∣AB and AB∣∣CD
∴ EF∣∣CD
∴ In ΔBCD, GF∣∣CD
⇒ F is the mid point of BC.
Similar questions