ABCD is a
trapezium in which AB ll CD
and p,q
are points
on AD and
BC
respectively such that PQ II DC if PD= 18 cm
BQ=35 cm
and
QC = 15cm, find AD
(A) 55cm
(B) 57 cm
(C) 60cm
(D)62 cm
Answers
Answered by
3
Answer:
60cm
Step-by-step explanation:
ap/pd=bc/qc
x/18=35/15
x=7x18/3
x=42
ad =ap+pd
=42+18
=60
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