ABCD is a trapezium in which AB parallel DC and P,Q are points on AD and BC respectively such that PQ parallel DC if PD = 18 cm and BQ = 35 cm and QC = 15 cm find AD
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Given: AB parellel DC
PD=18cm BQ=35cm QC= 15cm
PQ parellel DC that is AB parellel PQ
Construction: Join DB so that AND is a triangle and BDC is a triangle
Now, in ∆ABD and ∆BDC
AB parellel DC
Angle ABD=BDC(alternate interior angle)
Therefore AD=BC(sides opposite to equal angle are equal)
AD=BC
AD=BQ+ QC
AD=35+15=50cm
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