ABCD is a trapezium in which AB parallel DC. M and N are the mid- points of AD and BC respectively. if AB= 12 cm and MN = 14 cm, find CD
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Answer:
Given AB=12cm , MN=14cm
Since ,segment joining the mid-point of non-parallel sides of trapezium is half the sum of the lengths of its parallel sides.
⇒MN=
2
1
(AB+DC)
14=
2
1
(12+CD)
CD=28−12
CD=16cm
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