Question

ABCD is a trapezium in which AB parallel DC of ar ( triangle ABD ) = 24 cm square and AB = 8cm , then height of triangle ABC is : 3cm , 6cm , 4cm , 8cm .

Answer 1

Answer:

6cm.

Step-by-step explanation:

Take a look at the image.

Let h be the height of the triangle ABC. Now , we have the following data.

# ar (ABD)=24cm^2

# AB = 8cm

We can infer from the image that the height of the triangle ABD is the same as that of ABC. (AB||DC)

Now ar(ABD) =1/2 ( AB)(DD')

24 = 1/2 (h)(8)

h= 48÷8

h= 6cm

Hence the height of triangle ABC is also 6cm as told above.

Answer 2

Answer:

6cm

this is your correct answer