Question

ABCD is a trapezium in which AB parallel to CD if AD is equal to BC show that angle A is equal to Angle B and angle C is equals angleD

Answer 1

what is the question in it

Answer 2

Let us extend AB. Then, draw a line through C, which is parallel to AD, intersecting AE at point E

AD||CE ( by construction)

AE||DC ( as AB is extended to E)

It is clear that AECD is a parallelogram

(i) AD = CE (Opposite sides of parallelogram AECD)

However,

AD = BC (Given)

Therefore,

BC = CE

∠CEB = ∠CBE (Angle opposite to equal sides are also equal)

Consider parallel lines AD and CE. AE is the transversal line for them

∠A + ∠CEB = 1800 (Angles on the same side of transversal)

∠A + ∠CBE = 1800 (Using the relation CEB = CBE) ...(1)

However,

∠B + ∠CBE = 1800 (Linear pair angles) ...(2)

From equations (1) and (2), we obtain

∠A = ∠B

(ii) AB || CD

∠A + ∠D = 1800 (Angles on the same side of the transversal)

Also,

∠C + ∠B = 1800 (Angles on the same side of the transversal)

∠A + ∠D = ∠C + ∠B

However,

∠A = ∠B [Using the result obtained in (i)

∠C = ∠D

(iii) In ΔABC and ΔBAD,

AB = BA (Common side)

BC = AD (Given)

∠B = ∠A (Proved before)

ΔABC ΔBAD (SAS congruence rule)

(iv) We had observed that,

ΔABC ΔBAD

AC = BD (By CPCT)