ABCD is a trapezium in which ab parallel to CD if area of triangle ABC is equal to 24 cm square a b is equal to 8 cm find the height of the triangle ABC
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2
Answer:
area of triangle and parallelogram on the same parallel line and same base are equal .
so, area of triangle = 24 cm ^2
area of parallelogram = 24 cm ^2
base of parallelogram = 8cm
let height = x
area of parallelogram = base × height
24 = 8 *X
24/8 = x
3 = x
height of parallelogram = 3 cm .
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Answer:
6cm
Step-by-step explanation:
area of triangle is 24cm square
one parallel side ab is 8cm
area is 1/2bh
24cm square =1/2× 8cm× h
24=4×h
h=24/4
h=6cm
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