Math, asked by sdiya4649, 1 year ago

Abcd is a trapezium in which ab parallel to dc ab=16cm and dc=24cm. If e and f are midpoints ofad and bc respectively prove area of abfe =9/11area of efcd

Answers

Answered by Fareedahmed
4

Area of a trapezium ABCD = {¹/₂ × (AB + DC) × h} square units.

Proof:     Area of a trapezium ABCD 

            = area (∆DFA) + area (rectangle DFEC) + area (∆CEB) 

            = (¹/₂ × AF × DF) + (FE × DF) + (¹/₂ × EB × CE) 

           = (¹/₂ × AF × h) + (FE × h) + (¹/₂ × EB × h) 



            = ¹/₂ × h × (AF + 2FE + EB) 

            = ¹/₂ × h × (AF + FE + EB + FE) 

            = ¹/₂ × h × (AB + FE) 

            = ¹/₂ × h × (AB + DC) square units.

            = ¹/₂ × (sum of parallel sides) × (distance between them) 


Similar questions