ABCD is a trapezium in which AB parallel to DC &angle A=angle B=45degree.Find the angles C&D of the trapezium.
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Answered by
0
Answer:
135° each.
Step-by-step explanation:
Given ABCD is a trapezium with AB || CD and angle A = angle B = 45°.
Since, adjacent angles (angle A and angle B) are equal we can conclude that the trapezium ABCD is isosceles trapezium. Hence, angle C would also be equal to angle D. So let angle C = angle D be x
By angle sum property,
angle A + angle B + angle C + angle D = 360°
→ 45° + 45° + x + x = 360°
→ 2x + 90° = 360°
→ 2x = 360° - 90°
→ 2x = 270°
→ x = 270/2
→ x = 135°
135° each.
Step-by-step explanation:
Given ABCD is a trapezium with AB || CD and angle A = angle B = 45°.
Since, adjacent angles (angle A and angle B) are equal we can conclude that the trapezium ABCD is isosceles trapezium. Hence, angle C would also be equal to angle D. So let angle C = angle D be x
By angle sum property,
angle A + angle B + angle C + angle D = 360°
→ 45° + 45° + x + x = 360°
→ 2x + 90° = 360°
→ 2x = 360° - 90°
→ 2x = 270°
→ x = 270/2
→ x = 135°
Answered by
1
Answer:
Angle A + Angle D = 180° (consecutive interior.
angles )
Angle D = 180-45=135°
Angle D = Angle C = 135°
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