Abcd is a trapezium in which ab parallel to dc and it's diagonals intersects each other at the pot o show that ao/bo =co/do
Answers
Question :
ABCD is a trapezium in which AB || DC and its diagonals intersect each other at the point O.Show AO/BO = CO/DO
Given :
ABCD is a trapezium where AB||DC and diagonals AC and BD intersect each other at O.
To prove :
Solution :
From the point O,draw a line XO touching AD at X,in such a way that,XO||DC||AB
In triangle ADC,we have OX||DC
Therefore, by using basic proportionality theorem
--(i)
Now,in triangle ABD OX||AB
By using basic proportionality theorem
--(ii)
From equation (i) and (ii), we get,
Hence Proved.
Additional Information :
Basic proportionality theorem :
If a line is drawn parallel to one side of the triangle , Then the other sides are divided in the same ratio.
Here, We prove that
In trapezium ABCD , AO/BO = CO/DO
Using the Basic proportionality theorem.
We constructed OX || AB and proceeded with the problem.
Check out the attachment for detailed explanation.