Question

ABCD is a trapezium in which AB parallel to DC , BD is the diagonal and P is the midpoint of AD. A line is drawn through P, parallel to AB intersecting BC at Q. show that CQ is equal to QB​

Answer 1

Step-by-step explanation:

Given ABCD is a trapezium.

We have to prove, F is the mid point of BC, i.e., BF=CF

Let EF intersect DB at G.

In ΔABD E is the mid point of AD and EG∣∣AB.

∴ G will be the mid-point of DB.

Now EF∣∣AB and AB∣∣CD

∴ EF∣∣CD

∴ In ΔBCD, GF∣∣CD

⇒ F is the mid point of BC.

Answer 2

Answer:

RS

Step-by-step explanation:

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