ABCD is a trapezium in which ABC is a equlilateral triangle with area 9√3 sq.units. ∠ADC is 90°, the area of a trapezium in sq.units is
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Answer:
27√3/2
bro just make an equilateral triangle in the trapezium and as we know that in a pair of parallel lines the distance between them always same.so here the height of the equilateral triangle is equal to the height of the trapezium.so now apply the formula of area of triangle and find the height. by Pythagoras you can find the base of trapezium now apply area of trapezium.
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Step-by-step explanation:
27√3/2
bro this is just a simple solution just use your brain
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