ABCD is a trapezium in which Ad||BC, ABC =90°, AD=16cm, AC=41cm and BC=40cm.find the area of the trapezium.
Answers
Answer is 252.
AC = 41
AC = 41 BC = 40
AC = 41 BC = 40Now by phythogorus therom,
AC = 41 BC = 40Now by phythogorus therom,AC^2= AB^2+BC ^2. [Angle abc is 90°]
]AB^2= AC^2-BC ^2
]AB^2= AC^2-BC ^2 =41*41 - 40*40.
]AB^2= AC^2-BC ^2 =41*41 - 40*40. = 1681 - 1600
]AB^2= AC^2-BC ^2 =41*41 - 40*40. = 1681 - 1600 = 81
AB = 9
AREA OF TRAPEZIUM = 1/2 * (16+40) * 9
= 56/2 * 9 = 28*9 = 252.
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