Question

ABCD is a trapezium in which AD||BC.The diagonals AC and BD intersect at O. Prove that:area of triangle AOB=area of triangleCOD.

Answer 1

Explain: in given trapezium two diagonals intersect at point o. In triangle AOB and COD. <1=<2 BY alternate interior amgle, <3=<4 by alternate imterior angle and <5=<6 by vertically opposite angle.
So, triangle AOB =COD.