ABCD is a trapezium in which angle A: angle D= 5:7, angle B = (3x+11) & C =(5x-31). Find all the angles of the trapezium.
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given A:D = 5:7
let angles be 5x,7x
so 5x+7x+3x+11+5x-31 = 360
20x-20=360
20x = 360+20
20x = 380
x = 19
so A = 95
D = 133
B = 68
C = 64
let angles be 5x,7x
so 5x+7x+3x+11+5x-31 = 360
20x-20=360
20x = 360+20
20x = 380
x = 19
so A = 95
D = 133
B = 68
C = 64
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3
Answer:
/_ A = 75°, /_ D = 105° & /_ B = 86°
/_ C = 94°
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