ABCD is a trapezium in which angle ADC =117degree and angle ABC=147 degree.Find angle DAB and angle BCD
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Let angle DAB and angle BCD be x
Then,
147° + 117° + x + x = 360°
264° + 2x = 360°
2x = 360° - 264°
x = 96/2
x = 48°
Therefore,
Angle DAB and angle BCD are 48°.
Then,
147° + 117° + x + x = 360°
264° + 2x = 360°
2x = 360° - 264°
x = 96/2
x = 48°
Therefore,
Angle DAB and angle BCD are 48°.
awanishdubey:
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