Math, asked by aakkurd9987, 1 year ago

ABCD is a trapezium in which angleA equal to X +25,Angle B equal to angle Y and angle c equal to the angle 95 and angle D equals to the 2x+5 than find the value of x and y.

Answers

Answered by ingle0155
89

let in trapezium abcd

a=x+25

b=y

c=95

d=2x+5


seg ac is parallel to seg bd


hence ab and cd are transversal


so sum of measure of interior angle =180

angle a+ angle b= 180

x+25+y=180

x+y=180-25

x+y=155

y=155-x.....1


and angle c + angle d=180

95+2x+5=180

2x+100=180

2x=180-100

2x=80

x=40


put x=40 in 1

y=155-40

y=115


x=40

and y= 115

Answered by sajisharoon
22

Step-by-step explanation:

∠a = x + 25°

∠b = y

∠c = 95 °

∠d = 2x + 5

∠a + ∠b = 180 °

x + 25 + y = 180 °

x + y = 180° - 25°

x + y = 155°

y = 155° - x . . . . 1

∠c + ∠d = 180°

95° + 2x + 5= 180°  

2x + 100° = 180  °

2x = 180° - 100°

2x = 80°

x = 40  °

y = 155° - 40°

y = 115 °

x = 40 °

y = 115°

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