ABCD is a trapezium in which Jab is parallel to CD. if angle A is 36° and angle B is 81° , then find the angle C and angle D
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angle DAB+angle ABD+angle ADB=180
36+81+D=180
D=63°
angle ADC=126°
126°+36°+81°+angle C=360°
angle C=360-243
=117°
36+81+D=180
D=63°
angle ADC=126°
126°+36°+81°+angle C=360°
angle C=360-243
=117°
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