Question

ABCD is a trapezium in which the AB || DC. If the diagonal AC and BD intersect at O. Prove that ar(AOD)=ar(BOC).

PLEASE answer it fast .

Answer 1

Answer:

We know

ar(ADC) = ar(BCD) [ Δs on the same base and between same parallels]

Now, by subtracting ar(DOC) from both the sides,

ar(ADC) - ar(DOC) = ar(BCD) - ar(DOC)

ar(AOD) = ar(BOC).