ABCD is a trapezium inwhich AB parallel to DC.CD is produced to E such that CE=AB. Prove that area of triangle ABD = area of triangle BCE.
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Step-by-step explanation:
Given that
ABCD is a trapezium in which AB parallel to DC.CD is produced to E such that CE=AB.
To prove
Area of triangle ABD = area of triangle BCE.
Proof
As
CE =AB
SO THEY LIE ON SAME BASES
Area of triangle ABD = area of triangle BCE.
HENCE PROVED....
HOPE IT HELPS AND PLZ MARK IT AS BRAINLIEST
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Triangles between Over Same Base & Parallels Possess Equal Area
Step-by-step explanation:
Produce BA to M such that DM perpendicular BM and draw BN perpendicular DC.
Now, ar(△ABD) = ....(i)
ar(△BCE) = .....(ii)
Since, ΔABD and ΔBCE are between the same parallels. Therefore,
DM = BN .........(iii)
Also, AB = CE (Given) ............(iv)
From (iii) and (iv), we get
(CE \times BN)
⇒ ar (△ABD) = ar (△BCE) (Using (i) and (ii))
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