Question

Abcd is a trapezium of area 24.5 cm in 880 pal abc angle dab is equal to 90 degree is equal to 10 cm and bc is equal to 4 cm if abc is a quadrant of a circle find the area of the shaded region

Answer 1

Sol: Area of the trapezium = h/2 (a + b) where a and b are the parallel sides and h is the perpendicualr distance between the parallel sides. Area of the trapezium ABCD = AB/2 (AD + BC) 24.5 = (AB/2) (10 + 4) 49 = AB (14) AB = 3.5 cm Radius of the quadrant of the circle = AB = 3.5 cmArea of the quadrant of the circle = (1/4) (πr2) = (1/4) (22/7 x 3.5 x 3.5) = 9.625 cm2 Area of the shaded region = Area of the trapezium - Area of the quadrant of the circle                                       = 24.5 - 9.625                                       = 14.875 cm2

Answer 2

this is the answer for the given question that is given ad is 10 cm and bc is 4cm and area is 24.5 cm to find area of remaing area of shaded portion and also given that circle quadrant is 90 degree