Question

ABCD is a trapezium of area 91 centimetre square CD is parallel to a b and CD is longer than ab by 8 cm if the distance between a b and CD 7 cm find a b and CD

Answer 1

Let AB=x so CD = x+8

Given area of trapezium =91cm²
Area of trapezium=1/2(a+b)h
91=1/2(x+x+8)7
91=1/2(2x+8)7
91= 14x+56/2
91=14x/2+56/2
91=7x+28
91-28=7x
63/7=x
x= 9

so AB=9
and CD= x+8=17


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