ABCD is a trapezium of area 91 cm square CD is parallel to a b and CD is longer than ab and CD longer than ab by 8 cm if the distance between ab and cd is 7 cm find ab and Cd
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Reference of trapezium is in attachment.
AnswEr:-
Parallel sides of trapezium are 9 cm & 17 cm respectively.
Let the parallel sides be m & n cm respectively.
↠ n - m = 8
↠ n = m + 8 - - -(Eq.1)
Now we know,
☛ Area of trapezium = ½ × (Sum of parallel sides) × Distance
- Putting values:-
⇒ 91 = ½ (m + n) × 7
⇒ ½ (m + m + 8) = 91/7
⇒ ½ (2m + 8) = 13
⇒ ½ × 2(m + 4) = 13
⇒ m + 4 = 13
⇒ m = 13 - 4
⇒ m = 9
∴ One parallel side = 9 cm
Now putting value of m in (Eq.1)
⇒ n = 9 + 8
⇒ n = 17
∴ Another parallel side = 17 cm
Therefore,
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