Question

ABCD is a trapezium .P is the midpoint of BC.ABPD is a parallelogram.ar(ABPD)--ar(BPC)=10,Find the area of trapezium ABCD.​

Answer 1

Answer:

Given ABCD is a trapezium.

We have to prove, F is the mid point of BC, i.e., BF=CF

Let EF intersect DB at G.

In ΔABD E is the mid point of AD and EG∣∣AB.

∴ G will be the mid-point of DB.

Now EF∣∣AB and AB∣∣CD

∴ EF∣∣CD

∴ In ΔBCD, GF∣∣CD

⇒ F is the mid point of BC.

Answer 2

Step-by-step explanation:

The answer is clearly written along with diagram. Please mark me as Brainliest.