Question

ABCD is a trapezium, Show that area of trapezium ABCD is
h/2(a+b)​

Answer 1

Answer:

$area \: of \: trapezium \: \: = \frac{1}{2} = (sum \: of \: parellel \: side) \times height \\ \frac{1}{2} = (a + b) \times h$