ABCD is a trapezium such that AB||CD, angle A: angle D
= 2:1, angle B: angle C = 7:5. Find the angle B
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Answer:
2:1 is ratio of angle A and angle B
therefore,
let angle A be 2xand angle D be 1x
angle B and C are in the ratio of 7:5
therefore,
let angle B be 7x and angle C be 5x
In quadrilateral ABCD
A+B+C+D= 360 °(angle sum property of a quadrilateral)
therefore,
2x+7x+5x+1x =360°
15x = 360°
x = 360°/15
x = 72°
<B = 7x = 7× 72°
<B = 504°
same way we can find <A,<C and <D
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