ABCD is a trapezium such that AB || CD. If AC2 + BD2 13 cm and √AC x BD = 2√15 cm, then the sum of cubes of lengths of diagonals of ABCD is
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ABCD is a trapezium such that AB and CD are parallel and BC⊥CD. If ∠ADB=θ, BC=p and CD=q, then AB is equal to
cosα=
p
2
+q
2
q
and sinα=
p
2
+q
2
p
Using sine rule in triangle ABD
sinθ
AB
=
sin(θ+α)
BD
⇒AB=
sinθcosα+cosθsinα
p
2
+q
2
sinθ
=
p
2
+q
2
sinθ⋅q
+
p
2
+q
2
cosθ⋅p
p
2
+q
2
sinθ
⇒AB=
(pcosθ+qsinθ)
(p
2
+q
2
)sinθ
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