Question

ABCD is a trapezium such that AB || DC, angle A : angle D = 3 : 1 , angle B : angle C = 5 : 7 . find the angels of the trapezium.​

Answer 1

Answer:

Given,

∠A:∠D=3:1 and ∠B:∠C=5:7

Let

∠A and ∠B be 3x and x and

∠C and ∠D be 5x and 7x.

firstly,

A+D=180°(Alt.angles are supplementary)

=3x+x=180°

4x=180°

x=180/4=45°

ANGLE A=3x=3*45=135°

ANGLE D= x=45°

Now,

B+C=180°

5x+7x=180°

12x=180°

x=180/12=15°

ANGLE B=5x=5*15=75°

ANGLE C=7x=7*15=105°