Question

ABCD is a trapezium such that AB is parallel to CD. If angle A = LD = 7.2 and and LB : LC = 4:5. Find the four angles of the trapezium ​

Answer 1

Answer:

Angle A = Angle D = 72°

So, Angle B + Angle C = 360 - 144

                                     = 216°

We know that angles b & c are in the proportion 4:5 or 4x:5x

So, 216 = 9x

X  = 24

So, angle b and c are 96 and 120 respectively....

Therefore, all the angles are 72°(A) , 96°(B) , 120°(C) , 72°(D)