ABCD is a trapezium such that ABllCD and AB = 3cm.If the diagonals AC and BD intersect at O such that OA / OC = OB / OD = 1 / 2, then calculate DC
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Answer:
Given :
- ABCD is a trapezium
- BC || AD
- AB = 4 cm .
- If the diagonals AC and BD
- intersect at Ο such that AΟ/ΟC = DΟ/ΟB = 1/2
Now from the triangle ΔAOB and ΔCOD,
∠AOB = COD (vertically opposite angle)
AO/OC = DO/OB (Given)
from SAS congruent criterion,
ΔAOB ≅ ΔCOD
Now
AO/OC = BO/OD = AB/DC (since corresponding sides of similar traingles are preportional)
=> 1/2 = 4/DC
=> DC = 4 × 2
=> DC = 8 cm
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