ABCD is a trapezium such that DC = 3AB. If L and M are the midpoints of AD
and BC respectively, Show that LM = 2AB.
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Answer:
we know that in trapezium all sides are not equal
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Step-by-step explanation:
We have AB || DC.
∠ A and ∠ D are the interior angles on the same side of transversal line AD, whereas ∠ B and ∠ C are the interior angles on the same side of transversal line BC.
Now, ∠A + ∠D = 180∘
⇒ ∠D = 180∘ − ∠A
∴ ∠ D = 180∘ − 55∘ = 125∘
Again , ∠ B + ∠C = 180∘
⇒ ∠C = 180∘ − ∠B
∴ ∠ C = 180∘ − 70∘ = 110∘
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