Question

ABCD is a trapezium where AB||DC.E is the midpoint
of AD.A line drawn from E, parallel to AB, meets BC
at point F. Prove that F is the mid point of BC.​

Answer 1

Answer:

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Answer 2

Explanation:

Given ABCD is a trapezium.

We have to prove, F is the mid point of BC, i.e., BF=CF

Let EF intersect DB at G.

In ΔABD E is the mid point of AD and EG∣∣AB.

∴ G will be the mid-point of DB.

Now EF∣∣AB and AB∣∣CD

∴ EF∣∣CD

∴ In ΔBCD, GF∣∣CD

⇒ F is the mid point of BC.