Math, asked by abdulhaddinadeem, 2 months ago

ABCD is a trapezium with A,D parrallel to B,C. AB=16cm BC=20cm and ABC=115°
Find AC




show the perpendicular distance between BC and AD is 14.5cm




The area of trapezium ABCD is 348cm³






The area of triangle ACD is 203cm²



Hence or otherwise find CAD​

Answers

Answered by geetanjalikohok348
0

Step-by-step explanation:

ABCD is a trapezium with A,D parrallel to B,C. AB=16cm BC=20cm and ABC=115°

Find AC

show the perpendicular distance between BC and AD is 14.5cm

The area of trapezium ABCD is 348cm³

The area of triangle ACD is 203cm²

Hence or otherwise find CAD

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