ABCD is a trapezium with AB || CD. AB = 10.5 cm, CD = 15.5 cm and AM ICD. AM = 4.8 cm.
Find the area of the trapezium.
Two parallel sides ofa
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0
Step-by-step explanation:
Correct option is
A
1764
Draw CE∥DA and CF⊥AB.
Therefore, ADCE is a parallelogram having AE∥CD and CE∥DA.
⇒AD=CE=39cm,DC=AE=30cm and BE=75−30=45cm
In △BCE, by heron's formula we have
a=39cm,b=45cm and c=42cm
⇒s=2a+b+c=239+42+45=63cm
∴ Area of ΔBEC=s(s−a)(s−b)(s−c)
=63(63−39)(63−42)(63−45)cm2
=63×24×21×18cm2
=756cm2
Also, Area of ΔBEC=21×base×height
⇒21×45×h=
Answered by
3
Answer:
62.4cm.sq
Step-by-step explanation:
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