Math, asked by guptvandna, 6 months ago

ABCD is a trapezium with AB||CD. If AB = 11 cm, CD = 25 cm, AD = 15 cm and BC = 13 cm, find the area of trapezium ABCD.​

Answers

Answered by alimaheen66
2

Step-by-step explanation:

Here we will learn how to use the formula to find the area of trapezium.

Area of trapezium ABCD = Area of ∆ ABD + Area of ∆ CBD

= 1/2 × a × h + 1/2 × b × h

= 1/2 × h × (a + b)

= 1/2 (sum of parallel sides) × (perpendicular distance between them)

Area of trapezium

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Worked-out examples on area of trapezium

1. The length of the parallel sides of a trapezium are in the rat: 3 : 2 and the distance between them is 10 cm. If the area of trapezium is 325 cm², find the length of the parallel sides.

Solution:

Let the common ration be x,

Then the two parallel sides are 3x, 2x

Distance between them = 10 cm

Area of trapezium = 325 cm²

Area of trapezium = 1/2 (p₁ + p₂) h

325 = 1/2 (3x + 2x) 10

⇒ 325 = 5x × 5

⇒ 325 = 25x

⇒ x = 325/25

Therefore, 3x = 3 × 13 = 39 and 2x = 2 × 13 = 26

Therefore, the length of parallel sides area are 26 cm and 39 cm.

2. ABCD is a trapezium in which AB ∥ CD, AD ⊥ DC, AB = 20 cm, BC = 13 cm and DC = 25 cm. Find the area of the trapezium.

find the area of trapezium

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Solution:

From B draw BP perpendicular DC

Therefore, AB = DP = 20 cm

So, PC = DC - DP

= (25 - 20) cm

= 5 cm

Now, area of trapezium ABCD = Area of rectangle ABPD + Area of △ BPC

△BPC is right angled at ∠BPC

Therefore, using Pythagoras theorem,

BC² = BP² + PC²

13² = BP² + 5²

⇒ 169 = BP² + 25

⇒ 169 - 25 = BP²

⇒ 144 = BP²

⇒ BP = 12

Now, area of trapezium ABCD = Area of rectangle ABPD + Area of ∆BPC

= AB × BP + 1/2 × PC × BP

= 20 × 12 + 1/2 × 5 × 12

= 240 + 30

= 270 cm²

3. Find the area of a trapezium whose parallel sides are AB = 12 cm, CD = 36 cm and the non-parallel sides are BC = 15 cm and AG = 15 cm.

Let one side of trapezium is x, then other side parallel to it = 2x

Area of trapezium = 165 cm²

Height of trapezium = 10 cm

Now, area of trapezium = 1/2 (p₁ + p₂) × h

⇒ 165 = 1/2(x₁ + 2x) × 10

⇒ 165 = 3x × 5

⇒ 165 = 15x

⇒ x = 165/15

⇒ x = 11

Therefore, 2x = 2 × 11 = 22

Therefore, the two parallel sides are of length 11 cm and 22 cm.

These are the above examples explained step by step to calculate the area of trapezium

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