Question

ABCD is a trapezium with AB || DC, a line parallel to AC intersect AB at X ,BC at Y prove that ar.(∆ADX) congruent to ar.(∆ACY).​

Answer 1

Step-by-step explanation:

ar(adx) = ar (acx) ( lieng on the same base and b/w the same // lines are equal )...1

ar acx =ar acy ( lieing on the Same base and b/w the same // lines are equal )....2

from 1 and 2

ar adx = ar acy

hence proved