ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar (ADX) = ar (ACY). [Hint: Join CX.]
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ABCD is a trapezium with AB ∥ DC . A line parallel to AC intersects AB at X and BC at Y . Prove that ar(ADX) = ar(ACY)
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Given : ABCD is a trapezium with AB ∥ DC and XY ∥ AC. Join YA, XC and XD. Triangles ACX and ACY have same base AC and are between same parallels AC ...
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