Math, asked by supratikdasadhikari1, 1 month ago

ABCD is a trapezium with AB II CD, AB = 6, CD= 2. Diagonals AC, BD intersect at P such that Area of A PAD=12 sq. units. H 10. Area of A PDC = (in sq. units) a) 3 b) 4 C) 12 d) 16 Area of A PAB = (in sq. units) a) 48 b) 24 c) 36 d) 27 12. Area of trapezium ABCD= (in sq. units) a) 40 b) 48 C) 52 d) 6

Answers

Answered by garvitgolusingh123
0

Answer:

atleast send the picture. of trapeizum ABCD

Answered by arjunayush
0

Answer:

jddjbwkabfnejenenehekwmsn

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