Math, asked by yeshaahuja07, 10 days ago

ABCD is a trapezium with AB parallel to DC.
If AB = 10 cm, AD = BC = 4 cm and
ZDAB = LCBA = 60°, calculate
(i) the length of CD;
(ii) the distance between AB and CD. (ICSE)
—— Without cos or trigonometry pls answer fastttttt

Answers

Answered by saichavan

1

Answer:

1) CD=10cm

2) Distance between AB and CD is 4cm.

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