Question

ABCD is a trapezium with AD and BC as parallel sides and angle BAD=90°. BD and AC cut at E. Prove that triangle ABE is equal in area to triangle CED

Answer 1

Answer:

Given

Ad // BC

BAD=90

BD and AC cut at E

To proof ABE = CED

Proof

Here, as ABCD is a trapezium, therefore opposite sides are equal and parallel.

so we know that angles opposite to equal sides are also equal....

Here opposite sides are AB and CD and AD and BC

ABE and CED are opposite to AC and BD....

So ABE = CBE ....

proved....

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Answer 2

Answer:

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