Question

ABCD is a trapezium with side AB ǁ CD , if P & Q are the mid points of AD & BC respectively and AB = 5 cm &

Dc = 10 cm , find PQ. help hu​

Answer 1

Answer:

Answer

In △ABC, P, S are the mid points of AB, AC respectively.

So, PS∣∣BC and PS=21BC ---(i)

Similarly, in △ADC,

RS=21AD=21BC ---(ii)

In △BCD,

RQ=21BC ---(ii)

Similarly, in △ABD,

QP=21AD=21BC ---(iv)

∴From (i) (ii) (iii) (iv), we get

PQ=QR=RS=SP

Since all sides are equal, PQRS is a rhombus