Question

ABCD is a triangle BD is a diagonal of a rectangle which all congruence criterion can be used to show triangle ABD congruent triangle DCB ?
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Answer 1

Answer:

Given:

In rectangle ABCD ,

BD is diagonal.

To prove :

∆ABD is congruent to ∆DCB

BD=BD (common side)

AD=BC (opposite sides are equal in rectangle)

AB=DC ( " )

Therefore , ∆ABD is congruent to ∆DCB by SSS congruence criterion.