ABCD is an isosceles trapezium if angle A is 60 degree what is the measurement of angle B
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Given : ABCD is an isosceles trapezium
∠A = 60°
To Find : measurement of angle B
Solution:
Pair of parallel sides is not known hence there are two possible cases
Case 1:
AB || CD
then if ABCD is isosceles trapezium
Then ∠A = ∠B
=> ∠B = 60°
and ∠C = ∠D = 120° ( as ∠A + ∠D = 180° and ∠B + ∠C = 180°)
Case 2:
BC || AD
Then ∠A + ∠ B = 180°
=> ∠B = 120°
and ∠B = ∠C and ∠A = ∠D
∠B = 60° if AB || CD
∠B = 120° if BC || AD
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