Question

Abcd is an isosceles trapezium in which AB is parallel to DC angle a = 60° angle c = 100° find angle b and angle d . Also if AD is 5 cm then find BC

Answer 1

Answer:

C=80 andD=120

Step-by-step explanation:

B+C =180°

c=80

D=180-60

=120

Answer 2

Answer:

Step-by-step explanation:

Given:

ABCD is an isosceles trapezium.

$\angle A = 60^o \ and \angle\ C = 100^o$

Now we have to find  $\angle B \ and \angle\ D$

So,

$\angle A + \angle D = 180^o\\60^o + \angle D = 180^o \\\angle D = 180^o  - 60^o \\ \angle D = 120^o$

Now,

$\angle B + \angle C = 180^o\\ \angle  B +100^o = 180^o \\\angle B = 180^o  - 100^o \\ \angle B = 80^o$

Now we have,

$\angle B = 80^o, \angle D = 120^o$

In isosceles trapezium non parallel sides always equal.

Therefore, AD = BC = 5cm