Math, asked by simran666666, 10 months ago

ABCD is an isosceles trapezium in which angle C D A= 2x and Angle B A D = 3 x .find the angles of the trapezium.​

Answers

Answered by sameer1804
8

2x+3x=180°

5x=180°

x=36°.

angles are 36°,72°,72°,36°

Answered by Mithalesh1602398
0

Answer:

The angles of the trapezium is 36°,72°,72°,36°.

Step-by-step explanation:

Step : 1  An isosceles trapezium is a trapezium with equally sized non-parallel sides. In other words, the legs are equal in length and the bases are parallel.As ABCD is an isosceles trapezium. Hence, x = 36° and y = 108°.

Step : 2  An isosceles trapezoid's area may be calculated using the formula Area = (sum of parallel sides 2) height. A = (a + b) 2 h gives the area of a trapezium. Making a parallelogram out of two identical trapezia (or trapeziums) will demonstrate that this is the case. Rotate one trapezium 180 degrees. Use the trapezium's perpendicular height rather than its sloping height.

Step : 3 2x+3x=180°

5x=180°

x=36°.

angles are 36°,72°,72°,36°

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