Question

ABCD is an isosceles trapezium is parallel side is 13 cm and 25 CM its non parallel sides are equal and density find the area of the trapezium​

Answer 1

See attachement

Find EF:

EF = (25 - 13) ÷ 2 = 6 cm

FInd CD:

CD = EF = 6 cm

Find the height:

a² + b² = c²

a² + 6² = 10²

a² = 100 - 36

a² = 64

a = √64

a = 8 cm

Find the area of the trapezium:

Area = 1/2( a + b) h

Area = 1/2 ( 13 + 25) (8) = 152 cm²

Answer: The area is 152 cm²

Answer 2

Answer:

Very very sorry bro/sis for wasting your points

but the question is incomplete.You may delete my answer but I am telling for your good.Once again very very sorry.Please check the question once more. The length of the height or equal sides should be given.